From: | "Josh Berkus" <josh(at)agliodbs(dot)com> |
---|---|
To: | pgsql-sql(at)postgresql(dot)org |
Subject: | Re: Order by email address |
Date: | 2001-05-10 20:17:49 |
Message-ID: | web-54242@davinci.ethosmedia.com |
Views: | Raw Message | Whole Thread | Download mbox | Resend email |
Thread: | |
Lists: | pgsql-sql |
Herve,
> toto(at)aol(dot)com
> tutu(at)aol(dot)com
> toto(at)be(dot)com
> tutu(at)be(dot)com
> toto(at)yahoo(dot)com
>
> Is it possible and how ?
Given the relational rule of Atomicity (each discrete piece of
information shall have its own column or row), the solution is for you
to make "e-mail id" and "domain" seperate fields. Then you can sort:
ORDER BY mailbox, domain
If this is a legacy database, and splitting the field is not an option
for you due to exisiting applications/policy, then you'll need to write
a custom sorting function:
CREATE FUNCTION email_sort (VARCHAR)
RETURNS CHAR(120) AS '
DECLARE
email_addr ALIAS for $1;
mail_box CHAR(60);
mail_domain CHAR(60);
BEGIN
mail_box := CAST(SUBSTR(email_addr, 1, (STRPOS(email_addr, ''@'', 1)
-1)) AS CHAR(60));
mail_domain := CAST(SUBSTR(email_addr, (STRPOS(email_addr, ''@'', 1) +
1), 60) AS CHAR(60));
RETURN mail_box || mail_domain;
END;'
LANGUAGE 'plpgsql';
Then:
SELECT user_id, email, email_sort(email) as sortcol
FROM users
ORDER BY sortcol;
However, this solution has a number of problems for data integrity down
the line. If e-mail addresses are that important to your application, I
greatly encourage you to split the field.
-Josh Berkus
P.S. Roberto, please add the above to our function library.
______AGLIO DATABASE SOLUTIONS___________________________
Josh Berkus
Complete information technology josh(at)agliodbs(dot)com
and data management solutions (415) 565-7293
for law firms, small businesses fax 621-2533
and non-profit organizations. San Francisco
From | Date | Subject | |
---|---|---|---|
Next Message | Josh Berkus | 2001-05-10 20:38:21 | Re: Order by email address |
Previous Message | Bruce Momjian | 2001-05-10 19:47:57 | Re: Order by email address by domain ? |