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这篇博客介绍了如何解决LeetCode第82题，即如何从已排序的链表中删除所有重复的节点，保持链表的有序状态。文章通过示例展示了操作过程，并提出了解决方案。
Given the head of a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Return the linked list sorted as well.
Example 1:
Input: head = [1,2,3,3,4,4,5] Output: [1,2,5]
Example 2:
Input: head = [1,1,1,2,3] Output: [2,3]
Constraints:
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