swift 3 发送 HTTP 请求函数

最新推荐文章于 2024-08-10 07:38:21 发布

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本文介绍了一个使用Swift语言实现的网络请求方法，包括GET和POST两种请求方式。通过自定义函数进行HTTP请求，并设置请求头、参数及响应处理，适用于iOS和其他Swift支持的平台。

private func HttpPost(requestURL:String, postString:String) -> [String : AnyObject]
    {
        return HttpSync(requestURL: requestURL, postString: postString, method: "POST");
    }
    private func HttpGet(requestURL:String)->[String : AnyObject]{
        return HttpSync(requestURL: requestURL, postString: "", method: "GET");
    }
    private func HttpSync(requestURL:String, postString:String, method:String)->[String : AnyObject]{
        var request = URLRequest(url: URL(string:requestURL)!)
        request.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
        request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Accept")
        if(HttpMeta.Token != ""){
            request.setValue("BEARER " + HttpMeta.Token,forHTTPHeaderField: "Authorization");
        }
        
        request.httpMethod = method
        request.httpBody =  postString.data(using: String.Encoding.utf8);
        
        // print(request.debugDescription)
        
        var result:[String:AnyObject] = [:];
        
        let semaphore = DispatchSemaphore(value:0)
        
        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let data = data, error == nil else {
                //print(error ?? <#default value#>)
                return
            }
            
            do {
                print(data.debugDescription)
                print(response.debugDescription)
                let responseObject = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments)
                result = (responseObject as? [String : AnyObject])!;
                print(result)
                //  print(responseObject)
                
            } catch let jsonError {
                print(jsonError.localizedDescription)
                //  print("json error: \(jsonError.localizedDescription)")
            }
            
            semaphore.signal()
        }
        task.resume()
        
        _ = semaphore.wait(timeout: .distantFuture)
        
        return result
    }