E. Scuza

time limit per test

3 seconds

memory limit per test

256 megabytes

Timur has a stairway with nn steps. The ii-th step is aiai meters higher than its predecessor. The first step is a1a1 meters higher than the ground, and the ground starts at 00 meters.

The stairs for the first test case.

Timur has qq questions, each denoted by an integer k1,…,kqk1,…,kq. For each question kiki, you have to print the maximum possible height Timur can achieve by climbing the steps if his legs are of length kiki. Timur can only climb the jj-th step if his legs are of length at least ajaj. In other words, ki≥ajki≥aj for each step jj climbed.

Note that you should answer each question independently.

Input

The first line contains a single integer tt (1≤t≤1001≤t≤100) — the number of test cases.

The first line of each test case contains two integers n,qn,q (1≤n,q≤2⋅1051≤n,q≤2⋅105) — the number of steps and the number of questions, respectively.

The second line of each test case contains nn integers (1≤ai≤1091≤ai≤109) — the height of the steps.

The third line of each test case contains qq integers (0≤ki≤1090≤ki≤109) — the numbers for each question.

It is guaranteed that the sum of nn does not exceed 2⋅1052⋅105, and the sum of qq does not exceed 2⋅1052⋅105.

Output

For each test case, output a single line containing qq integers, the answer for each question.

Please note, that the answer for some questions won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language (like long long for C++).

Example

Input

Copy

 

3

4 5

1 2 1 5

1 2 4 9 10

2 2

1 1

0 1

3 1

1000000000 1000000000 1000000000

1000000000

Output

Copy

1 4 4 9 9 
0 2 
3000000000 

Note

Consider the first test case, pictured in the statement.

  • If Timur's legs have length 11, then he can only climb stair 11, so the highest he can reach is 11 meter.
  • If Timur's legs have length 22 or 44, then he can only climb stairs 11, 22, and 33, so the highest he can reach is 1+2+1=41+2+1=4 meters.
  • If Timur's legs have length 99 or 1010, then he can climb the whole staircase, so the highest he can reach is 1+2+1+5=91+2+1+5=9 meters.

In the first question of the second test case, Timur has no legs, so he cannot go up even a single step. :(

解题说明:此题是一道模拟题,根据题目意思, 需要记录每个台阶相应位置的总高度, 也就是求出前缀和 ,之后还要存储好到达所对应高度坐标中的 Tim所需要的跨越高度是多少,并记录到满足该条件后对应的前缀和下标是多少。这里采用upper_bound(a + 1, a + n + 1, x) - a - 1 在数组 a 中查找第一个大于 x 的元素的位置,然后返回该位置的前一个索引(即最后一个小于等于 x 的元素的位置)

#include<iostream>
#include<algorithm>
using namespace std;
int a[200005];
long long b[200005];

int main()
{
	int t, i, x, n, q;
	cin >> t;
	while (t--) 
	{
		cin >> n >> q;
		for (i = 1; i <= n; ++i) 
		{
			cin >> x;
			a[i] = max(a[i - 1], x);
			b[i] = b[i - 1] + x;
		}

		while (q--)
		{
			cin >> x;
			cout << b[upper_bound(a + 1, a + n + 1, x) - a - 1] << ' ';
		}
		cout << '\n';
	}
	return 0;
}

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值