python:实现是否为armstrong number阿姆斯特朗数
def is_armstrong_number(number):
sum = 0
# find the sum of the cube of each digit
temp = number
while temp > 0:
digit = temp %<
def is_armstrong_number(number):
sum = 0
# find the sum of the cube of each digit
temp = number
while temp > 0:
digit = temp %<