Create a Groovy Project
To create a basic Groovy project in Eclipse perform the following steps:
* Go to: File -> New -> Project
* Select Java Project and press Next
* In the Project Name field enter the name of your project (GroovyJava for this example)
* Under Project Layout select Create separate source and output folders and press Finish
* In the Package Explorer find the newly created project, right click, and select Groovy -> Add Groovy Nature
So far you should have a src folder, a bin-groovy folder, and several libraries. There is also a bin folder that was created by Eclipse, but is hidden due to
exclusion filters. The next steps are needed to make the bin-groovy folder the default output folder, and to connect it to the src folder so that the
debugger will know where to find the associated source and classes:
* In the Package Explorer, right click on the "GroovyJava" project, and select: Build Path -> Configure Build Path
* Select the Source tab and then use the Browse button to change the Default Output Folder from bin to bin-groovy
* Press OK, OK
This will expose the bin folder in the Package Explorer. I'm not sure why the plugin creates a bin-groovy directory. Perhaps there are other "bin" files that
are best kept separate from the Groovy classes, or perhaps one of the original versions of Eclipse didn't create a "bin" directory automatically. Some day
when someone has a clear idea of the usefulness of this, or lack thereof, we can clean up my instructions.
创建一个groovy工程
为了在eclipse中创建一个基本的groovy工程你需要以下步骤:
*点击菜单File->New->Project
*选择java project然后点击next
*在工程名的字段(Project Name)中填写你的工程名(在这个例子中可以以GroovyJava命名)
*在工程布局器下选择创建独立源以及输出目录并点击结束(有些是英文啦,可能直接显示的就是finish)
*在Package Explorer(包浏览器)找到新建立的工程,点击右键,选择Groovy->Add ZGroovy Nature
到现在你应该有一个src文件夹,一个bin-groovy文件夹,以及几个lib库。当然还有一个被Ecllipse创建的bin文件夹,但它已经利用exclusino filters(Eclipse的排除过滤器)
隐藏起来了。接下来要让bin-groovy文件夹成为默认的输出文件夹,并且把bin-groovy与src文件夹连接起来以便调试器知道从哪儿找到关联的源文件和类:
*在Package Explorer(包浏览器)找到新建立的工程,点击右键选择Build Path->Configure Build Path
*选择Source选项卡利用Browse button改变默认的输出文件夹为bin-groovy,原来可是bin文件夹哟
*然后就是点击 OK OK
这些工作做完后原来隐藏的bin文件夹将为出现在Package Explorer(包浏览器)。我不知道为什么groovy的插件要建立一个bin-groovy 的文件夹。或许有其它的"bin"文件夹里的文
件要和Groovy的类文件分开?也可能在Eclipse的早期版本不提供"bin"文件夹的自动建立?如果有人清楚这种做法的原因我们可能一起完善我的这人操作指南。
To create a basic Groovy project in Eclipse perform the following steps:
* Go to: File -> New -> Project
* Select Java Project and press Next
* In the Project Name field enter the name of your project (GroovyJava for this example)
* Under Project Layout select Create separate source and output folders and press Finish
* In the Package Explorer find the newly created project, right click, and select Groovy -> Add Groovy Nature
So far you should have a src folder, a bin-groovy folder, and several libraries. There is also a bin folder that was created by Eclipse, but is hidden due to
exclusion filters. The next steps are needed to make the bin-groovy folder the default output folder, and to connect it to the src folder so that the
debugger will know where to find the associated source and classes:
* In the Package Explorer, right click on the "GroovyJava" project, and select: Build Path -> Configure Build Path
* Select the Source tab and then use the Browse button to change the Default Output Folder from bin to bin-groovy
* Press OK, OK
This will expose the bin folder in the Package Explorer. I'm not sure why the plugin creates a bin-groovy directory. Perhaps there are other "bin" files that
are best kept separate from the Groovy classes, or perhaps one of the original versions of Eclipse didn't create a "bin" directory automatically. Some day
when someone has a clear idea of the usefulness of this, or lack thereof, we can clean up my instructions.
创建一个groovy工程
为了在eclipse中创建一个基本的groovy工程你需要以下步骤:
*点击菜单File->New->Project
*选择java project然后点击next
*在工程名的字段(Project Name)中填写你的工程名(在这个例子中可以以GroovyJava命名)
*在工程布局器下选择创建独立源以及输出目录并点击结束(有些是英文啦,可能直接显示的就是finish)
*在Package Explorer(包浏览器)找到新建立的工程,点击右键,选择Groovy->Add ZGroovy Nature
到现在你应该有一个src文件夹,一个bin-groovy文件夹,以及几个lib库。当然还有一个被Ecllipse创建的bin文件夹,但它已经利用exclusino filters(Eclipse的排除过滤器)
隐藏起来了。接下来要让bin-groovy文件夹成为默认的输出文件夹,并且把bin-groovy与src文件夹连接起来以便调试器知道从哪儿找到关联的源文件和类:
*在Package Explorer(包浏览器)找到新建立的工程,点击右键选择Build Path->Configure Build Path
*选择Source选项卡利用Browse button改变默认的输出文件夹为bin-groovy,原来可是bin文件夹哟
*然后就是点击 OK OK
这些工作做完后原来隐藏的bin文件夹将为出现在Package Explorer(包浏览器)。我不知道为什么groovy的插件要建立一个bin-groovy 的文件夹。或许有其它的"bin"文件夹里的文
件要和Groovy的类文件分开?也可能在Eclipse的早期版本不提供"bin"文件夹的自动建立?如果有人清楚这种做法的原因我们可能一起完善我的这人操作指南。