#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
/*
本题是对背包知识的复习题, 综合应用了, 背包前三讲的内容;
对于复习很有帮助。
*/
struct node
{
int v;
int m;
}s[10];
int temp;
int dp[200005];
void completePake(int v)
{
for(int j = v; j <= temp; j++) {
dp[j] = max(dp[j], dp[j - v] + v);
}
}
void zeroOnePake(int v) {
for(int j = temp; j >= v; j--) {
dp[j] = max(dp[j], dp[j - v] + v);
}
}
void solve(int v, int m) {
if(v*m >= temp) {
completePake(v); //完全背包
return;
}
int t = 1;
while(t < m) { //多重背包
zeroOnePake(t*v); //01背包
m -= t;
t<<=1;
}
zeroOnePake(v*m);
}
int main()
{
int q = 1;
while(1) {
int sum = 0;
for(int i = 1; i <= 6; i++) {
scanf("%d", &s[i].m);
s[i].v = i;
sum += s[i].m * i;
}
if(sum == 0)
break;
printf("Collection #%d:\n", q++);
temp = sum/2;
if(temp*2 == sum)
{
for(int i = 0; i < sum; i++)
dp[i] = -999999;
dp[0] = 0;
for(int i = 1; i <= 6; i++) {
solve(s[i].v, s[i].m);
}
if(dp[temp] < 0)
printf("Can't be divided.\n");
else
printf("Can be divided.\n");
}
else
printf("Can't be divided.\n");
printf("\n");
}
return 0;
}