JAVA中FileHelper的一个用法

最新推荐文章于 2021-05-18 21:33:03 发布

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最新推荐文章于 2021-05-18 21:33:03 发布

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文章标签： java exception null string buffer file

本文链接：https://blog.csdn.net/masuwen/article/details/5159558

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public boolean writeXML(String content, String filename)
    {
        String savepath;
        FileOutputStream fout;
//        log.info("content:"+content+" filename:"+filename+" writeDir:"+writeDir);
        savepath = (new StringBuilder(String.valueOf(writeDir))).append(File.separatorChar).append(filename).toString();
        fout = null;
        if(content == null)
            return false;
        File file = new File(writeDir);
        try
        {
        if(!file.exists()){
          file.mkdirs();
        }
            fout = new FileOutputStream(savepath);
            byte buffer[] = content.getBytes();
            fout.write(buffer);
           // break MISSING_BLOCK_LABEL_111;
        }
        catch(Exception e)
        {
            e.printStackTrace();
        }
        if(fout != null)
            try
            {
                fout.close();
            }
            catch(IOException e)
            {
                return false;
            }
       // return false;
       // Exception exception;
       // exception;
        if(fout != null)
            try
            {
                fout.close();
            }
            catch(IOException e)
            {
                return false;
            }
        //throw exception;
        if(fout != null)
            try
            {
                fout.close();
            }
            catch(IOException e)
            {
                return false;
            }
        return true;
    }