&&与||的妙用

据说是EMC的笔试题

写一个函数int func(int i, int N){(1);}，输出

i

i+1

...

N

N-1

...

i

要求用一个语句完成，不能用for,while等等。

#include <stdio.h> /* * give a function interface int func(int i, int N) where i <= N, * print i, i+1, ..., N, N, N-1, ..., i. * can just use one statement, and can not use statements such as * if, for, do, while, ? : */ int func(int i, int N) { return !((i < N) && printf("%d/n", i) && func(i + 1, N) || printf("%d/n", i)); } int func2(int i, int N) { return (i == N) && printf("%d/n", i) || printf("%d/n", i) && func2(i + 1, N) && printf("%d/n", i); } int main() { func(1, 5); printf("*************/n"); func2(1, 5); printf("*************/n"); return 0; }