输入一段英文文字，筛选出其中的元音字母及个数。

最新推荐文章于 2024-03-31 09:08:12 发布

lemmon_tree

最新推荐文章于 2024-03-31 09:08:12 发布

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分类专栏： c语言学习笔记文章标签： c语言

本文链接：https://blog.csdn.net/lemmon_tree/article/details/122342826

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版本一：switch，case多重标签的代码

#include <stdio.h>

int main(void) {
	int a_ct, e_ct, i_ct, o_ct, u_ct ;
	a_ct = e_ct = i_ct = o_ct = u_ct = 0;
	char ch;
	printf("Enter some text,enter # to quit.\n");
	while ((ch = getchar()) != '#') {
		switch (ch) {
			case 'a':
			case 'A':
				a_ct++;
				break;
			case 'e':
			case 'E':
				e_ct++;
				break;
			case 'i':
			case 'I':
				i_ct++;
				break;
			case 'o':
			case 'O':
				o_ct++;
				break;
			case 'u':

			case'U':

				u_ct++;
				break;
			default:
				break;

		}

	}
	printf("Number of vowles:A	E	I	O	U\n");
	printf("				 %4d%4d%4d%4d%4d\n", a_ct, e_ct, i_ct, o_ct, u_ct);
	return 0;
}

版本二：无多重标签，要用到toupper()函数

#include <stdio.h>
//toupper()函数的库函数
#include <ctype.h>

int main(void) {
	int a_ct, e_ct, i_ct, o_ct, u_ct ;
	a_ct = e_ct = i_ct = o_ct = u_ct = 0;
	char ch;
	printf("Enter some text,enter # to quit.\n");
	while ((ch = getchar()) != '#') {
		ch = toupper(ch);
		switch (ch) {

			case 'A':
				a_ct++;
				break;

			case 'E':
				e_ct++;
				break;

			case 'I':
				i_ct++;
				break;

			case 'O':
				o_ct++;
				break;


			case'U':

				u_ct++;
				break;
			default:
				break;

		}

	}
	printf("Number of vowles:A	E	I	O	U\n");
	printf("				 %4d%4d%4d%4d%4d\n", a_ct, e_ct, i_ct, o_ct, u_ct);
	return 0;
}