problem 1338: ugly numbers

本文介绍了一种通过编程解决Ugly Numbers问题的方法。Ugly Numbers是指仅包含质因数2、3或5的数。文章提供了完整的C语言实现代码,并采用最小值选择策略来生成指定位置的Ugly Number。

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Ugly Numbers
Time Limit:1000MS  Memory Limit:10000K
Total Submit:2558 Accepted:1121

Description
Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, ...
shows the first 10 ugly numbers. By convention, 1 is included.
Given the integer n,write a program to find and print the n'th ugly number.

Input
Each line of the input contains a postisive integer n (n <= 1500).Input is terminated by a line with n=0.

Output
For each line, output the n’th ugly number .:Don’t deal with the line with n=0.

Sample Input

 
 
1
2
9
0

Sample Output

1
2
10

Source
New Zealand 1990 Division I,UVA 136

my solution:

Source

Problem Id:
1338   User Id:keepRunning 
Memory:32K  Time:0MS
Language:C  Result:Accepted

Source 

#include
< stdio.h >

int  r[ 1501 ];
int  Min( int  a, int  b, int  c) {
    
if(a<b)b=a;
    
if(b<c)c=b;
    
return c;
}
    
int  main() {
    
int a;
    
int b;
    
int c;
    
int i;
    
int j;
    
    r[
1]=1;r[2]=2;r[3]=3;r[4]=4;r[5]=5;
    a
=3; b=2;  c=2;  
    
for(i=6;i<=1500;i++){
        r[i]
=Min(r[a]*2,r[b]*3,r[c]*5);
        
for(;r[a]*2<=r[i];a++);
        
for(;r[b]*3<=r[i];b++);
        
for(;r[c]*5<=r[i];c++);
    }

    scanf(
"%d",&i);
    
while(i){
        printf(
"%d ",r[i]);
        scanf(
"%d",&i);
    }

    
return 0;
}
        


 

 

 

 

 
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