使用Axis2传递简单Java对象（POJO）

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最新推荐文章于 2022-06-04 14:31:13 发布

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文章标签： Java Apache Tomcat XML Web

本文介绍如何使用Axis2在Web Service中传递Java对象。

author: ZJ 07-5-7

Blog: http://zhangjunhd.blog.51cto.com/

在Axis2_1.2版本中提供了传递Java对象的功能（注：只有1.1/1.2版本提供，更早的Axis2版本没有此功能）。此项功能称为传输POJO(a Plain Old Java Object)

1.引入一个简单的POJO- The Weather POJO

Weather.java

package sample.pojo.data;

public class Weather {

?????? float temperature;

?????? String forecast;

?????? boolean rain;

?????? float howMuchRain;

?????? public void setTemperature(float temp) {

????????????? temperature = temp;

?????? }

?????? public float getTemperature() {

????????????? return temperature;

?????? }

?????? public void setForecast(String fore) {

????????????? forecast = fore;

?????? }

?????? public String getForecast() {

????????????? return forecast;

?????? }

?????? public void setRain(boolean r) {

????????????? rain = r;

?????? }

?????? public boolean getRain() {

????????????? return rain;

?????? }

?????? public void setHowMuchRain(float howMuch) {

????????????? howMuchRain = howMuch;

?????? }

?????? public float getHowMuchRain() {

????????????? return howMuchRain;

?????? }

}

Note that it's all just straight POJOs with field items and getter and setter methods for each field.

2.基于此POJO的service

WeatherService.java

package sample.pojo.service;

import sample.pojo.data.Weather;

public class WeatherService{

??? Weather weather;

???

??? public void setWeather(Weather weather){

??????? this.weather = weather;

??? }

??? public Weather getWeather(){

??????? return this.weather;

??? }

}

3.相应的services.xml

??? <description>Weather POJO Service</description>

??? <messagereceivers>

??????? <messagereceiver <="" font="">

??????????? mep="http://www.w3.org/2004/08/wsdl/in-only"

??? class="org.apache.axis2.rpc.receivers.RPCInOnlyMessageReceiver"/>

??????? <messagereceiver< font="">

??????????? mep="http://www.w3.org/2004/08/wsdl/in-out"

??? class="org.apache.axis2.rpc.receivers.RPCMessageReceiver"/>

??? </messagereceivers>

??? <parameter name="ServiceClass">

??????? sample.pojo.service.WeatherService

??? </parameter>

</service>

4.打包与部署

将文件组织成：

- WeatherService

?? - META-INF

???? - services.xml

?? - sample

???? - pojo

?????? - data

???????? - Weather.class

?????? - service

???????? - WeatherService.class

将其打包为WeatherService.aar，并部署在Tomcat上（详见 基于Tomcat5.0和Axis2开发Web Service应用实例 ）。

5．测试

WeatherRPCClient.java

package sample.pojo.rpcclient;

import javax.xml.namespace.QName;

import org.apache.axis2.AxisFault;

import org.apache.axis2.addressing.EndpointReference;

import org.apache.axis2.client.Options;

import org.apache.axis2.rpc.client.RPCServiceClient;

import sample.pojo.data.Weather;

public class WeatherRPCClient {

?????? public static void main(String[] args1) throws AxisFault {

????????????? RPCServiceClient serviceClient = new RPCServiceClient();

????????????? Options options = serviceClient.getOptions();

????????????? EndpointReference targetEPR = new EndpointReference(

??????????????????????????? "http://localhost:8080/axis2/services/WeatherService");

????????????? options.setTo(targetEPR);

????????????? // Setting the weather

????????????? QName opSetWeather = new QName("http://service.pojo.sample/xsd",

??????????????????????????? "setWeather");

????????????? Weather w = new Weather();

????????????? w.setTemperature((float) 39.3);

????????????? w.setForecast("Cloudy with showers");

????????????? w.setRain(true);

????????????? w.setHowMuchRain((float) 4.5);

????????????? Object[] opSetWeatherArgs = new Object[] { w };

????????????? serviceClient.invokeRobust(opSetWeather, opSetWeatherArgs);

????????????? // Getting the weather

????????????? QName opGetWeather = new QName("http://service.pojo.sample/xsd",

??????????????????????????? "getWeather");

????????????? Object[] opGetWeatherArgs = new Object[] {};

????????????? Class[] returnTypes = new Class[] { Weather.class };

????????????? Object[] response = serviceClient.invokeBlocking(opGetWeather,

??????????????????????????? opGetWeatherArgs, returnTypes);

????????????? Weather result = (Weather) response[0];

????????????? if (result == null) {

???????????????????? System.out.println("Weather didn't initialize!");

???????????????????? return;

????????????? }

????????????? // Displaying the result

????????????? System.out.println("Temperature?????????????? : "

??????????????????????????? + result.getTemperature());

????????????? System.out.println("Forecast????????????????? : "

??????????????????????????? + result.getForecast());

????????????? System.out.println("Rain????????????????????? : " + result.getRain());

????????????? System.out.println("How much rain (in inches) : "

??????????????????????????? + result.getHowMuchRain());

?????? }

}

6．结果

Temperature?????????????? : 39.3

Forecast????????????????? : Cloudy with showers

Rain???????????????? ????: true

How much rain (in inches) ???: 4.5

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