Given a string containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, determine if the input string is valid.
The brackets must close in the correct order, "()"
and "()[]{}"
are all valid but "(]"
and "([)]"
are not.
思路:使用堆栈存储,遇到配对就弹出,为空则恰好全部配对成功。
import java.util.Stack;
public class Solution {
public boolean isValid(String s) {
Stack<Character> stack = new Stack<>();
for (int i = 0; i < s.length(); i++) {
char ch = s.charAt(i);
switch (ch) {
case ')':
if (!stack.isEmpty() && stack.peek() == '(') {
stack.pop();
} else {
stack.push(ch);
}
break;
case ']':
if (!stack.isEmpty() && stack.peek() == '[') {
stack.pop();
} else {
stack.push(ch);
}
break;
case '}':
if (!stack.isEmpty() && stack.peek() == '{') {
stack.pop();
} else {
stack.push(ch);
}
break;
default:
stack.push(ch);
}
}
return stack.isEmpty();
}
}