Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
//利用set记录每次得到的平方和,当出现非1的重复平方和时,返回False,否则,返回True
class Solution {
public:
bool isHappy(int n) {
set<int> set1;
if (n <= 0) return false;
if (n == 1) return true;
int sum = 0;
int p = 0;
while (n!=1 ){
while (n){
p = n % 10;
n = n / 10;
sum = sum + p*p;
}
if (set1.find(sum)!=set1.end())
return false;
n = sum;
sum = 0;
set1.insert(n);
}
return n == 1;
}
};