题目大意:给前和中,求后序遍历
#include<iostream>
#include<cstring>
#include<cmath>
#include<cstdio>
using namespace std;
int main()
{
char s[255],s1[255];
scanf("%s",s);
scanf("%s",s1);
int len=strlen(s);
int sum=1,k=0;
for (int i=0;i<=len-1;i++)
{
k=0;
for (int j=0;j<=len;j++)
if (s[i]==s1[j])
{
k=j;
break; //找它在后序遍历中出现的位置。ps:c+没pos函数真心不爽
}
if ((k!=0)&&(s1[k-1]==s[i+1])) sum<<=1; //判断成功就sum=sum<<1
}
cout<<sum;
}