归并排序是稳定排序,且其最好,最坏,平均时间复杂度均为O(nlogn);
#include<stdio.h>
#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;
//快速排序
void merge(vector<int>& nums, int low, int mid, int high, vector<int> temp)//nums一定是引用,不然排序后返回的还是原来的顺序
{
int k = 0;
int i = low;
int j = mid + 1;
while (i <= mid && j <= high)
{
if (nums[i] <= nums[j])
temp[k++] = nums[i++];
else
temp[k++] = nums[j++];
}
while(i<=mid) //后半部分已经遍历完,前半部分还有
temp[k++] = nums[i++];
while (j<=high)//前半部分已经遍历完,后半部分还有
temp[k++] = nums[j++];
for (int i = 0; i < k; i++) //这一步一定要写,将有序的数组写回nums
nums[low + i] = temp[i];
}
void mergesort(vector<int> &nums, int low, int high, vector<int> temp)
{
if (low < high)
{
int mid = (low + high) >> 1;
mergesort(nums, low, mid, temp);//前半部分有序
mergesort(nums, mid + 1, high, temp);//后半部分有序
merge(nums, low, mid, high, temp);//对两个已经有序的子部分进行合并;
}
}
int main()
{
vector<int> nums{1,4,2,3,5,9,8,6,7,0,10,14,23,20,19,68};
vector<int> res(nums.size());
mergesort(nums,0,nums.size()-1,res);
return 0;
}