Coding_Czx的博客

双重for循环，vector二维数组

列举前几项，易发现答案为斐波那契数列前m项求和#include <iostream>using namespace std;int main() { long long m, a = 1, b = 2, ans = 3; const long long M = 998244353; cin >> m; if (m == 1) { cout << 1; return 0; } else ..

#include<iostream>#include<cmath>#include<iomanip>#include<string>#include<algorithm>using namespace std;int main(){ string s; getline(cin, s); int length = s.size(); string in; getline(cin, i...

原代码：#include <iostream>#include<cmath>#include<iomanip>#include<string>using namespace std;void sort (int *length){ for (int i = 0; i < 3; i++) { for (int j = 0; j < 3 - i; j++)//从小到大 { if (length[j] >...

原代码：#include<iostream>using namespace std;int main(){ int arr[5]; for (int i = 0; i < 5; i++) { cin >> arr[i]; } int sum = 0; //int a, b, c, d, e; int out = 0; for (int i = 0; i < 5; i++) { out = arr[i] / 3; s...

除了\t外，还能用<iomanip>头文件里的setw（）函数来处理对齐输出。本题主要考察输出流的控制。setw() 函数setw()函数可以控制输出流的下一个输出内容的场宽。以下是一个使用的例子。当运行以下语句时：int a=114514;cout<<a;输出结果将为：114514当包含了头文件<iomanip>，并运行以下语句时：int a=114514;cout<<setw(10)<<1.

我的解法：#include<iostream>#include<cmath>using namespace std;double calculate(int num)//1+2+……+10n{ double max = pow(10, num); double sum = 0; for (double i = 1; i <= max; i++) { sum = sum + i; } return sum;}int main(){...

#include<iostream>#include<cmath>using namespace std;int main(){ int k; while (cin >> k) { long long sum = 0; for (int i = 1; i <= k; i++) { sum = sum + pow(i, 3); } cout << sum << endl; } return 0...

#include<iostream>using namespace std;int min(int salary){ int minNum = 0; int hundred, fifty, ten, five, two, one; if (salary == 1||salary==2 || salary == 5 || salary == 10 || salary == 50 || salary == 100) { minNum...

纠结的点：多行输入#include<iostream>#include<cmath>using namespace std;int main(){ int n, m; while (cin >> m >> n) { int count=0; for (int num = m; num <= n; num++) { if ((pow((num / 100), 3) + pow((num / 10)%10,..