python读取Excel指定单元格的值

cnblogs_user

已于 2024-07-09 16:51:21 修改

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文章标签： excel

于 2024-07-09 16:49:29 首次发布

本文链接：https://blog.csdn.net/cnblogs_user/article/details/140300468

使用openpyxl实现

只支持xlsx文件，不支持xls

import openpyxl


def read_cell(io, sheet, cell='A2'):
    """
    读取单元格
    :param io: Excel文件路径
    :param sheet: 读取哪一张表，str, int   eg: 'Sheet1' or 0
    :param cell: 读取哪一个单元格
    :return: value --> str
    """
    excel = openpyxl.load_workbook(io)
    if isinstance(sheet, str):
        ws = excel[sheet]
    elif isinstance(sheet, int):
        name = excel.sheetnames[sheet]
        ws = excel[name]
    else:
        raise TypeError('sheet must be int or str, not %s' % type(sheet))
    val = ws[cell].value
    if val:
        return val
    return ''

使用xlrd实现

只支持xls（version > 2.x），既支持xls又支持xlsx（version < 2.x）

import xlrd


def get_index(capital):
    """
    大写字母（Excel列头）转数字
    :param capital: 'A' --> 0, 'AA' --> 26
    :return: int
    """
    number = 0
    capital = capital.upper()
    for char in capital:
        number = number * 26 + ord(char) - ord('A') + 1
    return number - 1


def read_cell(io, sheet, cell='A1'):
    """
    读取单元格
    :param io: Excel文件路径
    :param sheet: 读取哪一张表，str, int   eg: 'Sheet1' or 0
    :param cell: 读取哪一个单元格
    :return: value --> str
    """
    wb = xlrd.open_workbook(io)
    if isinstance(sheet, str):
        ws = wb.sheet_by_name(sheet)
    elif isinstance(sheet, int):
        ws = wb.sheet_by_index(sheet)
    else:
        raise TypeError('sheet must be int or str, not %s' % type(sheet))
    pos_col, pos_row = re.findall('[A-Z]+|[0-9]+', cell)
    col_index = get_index(pos_col)
    value = ws.col_values(col_index, start_rowx=int(pos_row) - 1, end_rowx=int(pos_row))
    if value:
        return value[0]
    return ''