有一个二维数组杨氏矩阵,数组的每行从左到右是递增的,每列从上到下是递增的,在这样的数组中查找一个数字是否存在
#include <stdio.h>
#define ROW 4
#define COL 4
int Yang(int arr[ROW][COL],int val)
{
int i = 0;
int j = COL - 1;
int tmp = arr[i][j];
while(1)
{
if(tmp == val)
{
return 1;
}
else if(tmp < val && j >= 0)
{
tmp = arr[++i][j];
}
else if(tmp > val &&j >= 0)
{
tmp = arr[i][--j];
}
else
{
return 0;
}
}
}
int main()
{
int a[ROW][COL] = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16};
int i = 0;
int j = 0;
int num;
printf("数组为:\n");
for(i = 0; i<ROW; i++)
{
for(j = 0; j < COL; j++)
{
printf("%5d",a[i][j]);
}
printf("\n");
}
printf("Please Enter:");
scanf("%d",&num);
if(Yang(a,num))
{
printf("%d在该数组中\n",num);
}
else
{
printf("%d不在该数组中\n",num);
}
return 0;
}