scanner console = new Scanner（System.in）啥意思啊?

Scanner scanner = new Scanner(System.in);

Scanner sc = new Scanner(System.in);

Create a new class that reads the conversation.txt line by line and prints it to the console. In this class you should implement two different methods to read the file: 1. Implement a method using a Scanner that reads the file. (Successfully printing file content to Console: 1P) 2. Implement a method that uses a BufferedReader to read the file. (Successfully printing file content to Console: 1P) Finally, alter the second method that reads the file line by line using a BufferedReader. After printing the first two lines, make your programme wait for the user to press enter before printing the next two lines. Continue this until all the lines are printed. Once the end of the file is reached, the programme should terminate so that when the user presses enter again, nothing bad happens. Hint: You can use a Scanner which reads from the system input stream like this Scanner s = new Scanner(System.in); to wait for user input.

用java补全下列代码/** * 计算数组中元素的距离 * 给定一个字符串数组strs，在给定2个字符串str1和str2，返回在strs中str1与str2的最小距离，如果str1或str2为null，或不在strs中，返回-1 * 例如： * 【数组】{"abc","cde","bcd","ac","bcd","ac"} * 【两个字符串】“abc","ac" * 【输出】最小距离为：3 */ public class AfterClassTest02 { public static void main(String[] args) { String[] strs={"abc","cde","bcd","ac","bcd","ac"}; System.out.println("数组："+ Arrays.toString(strs)); Scanner console=new Scanner(System.in); System.out.println("请输入两个字符串："); String str1=console.next(); String str2=console.next(); for(int i=0;i<strs.length;i++){ if(str1.equals(strs[i])){ int sort1=i; System.out.println("str1:"+(sort1+1)); } // else{ // System.out.println("str11"+"-1"); // //break; // } } for(int j=0;j<strs.length;j++) { if (str2.equals(strs[j])) { int sort2 = j; System.out.println("str2:" + (sort2 + 1)); } // else { // System.out.println("str22" + "-1"); // break; // } } } }