LeetCode-184. 部门工资最高的员工( Customers Who Never Order)。

本文链接：https://blog.csdn.net/Hello_JavaScript/article/details/98852451

Employee 表包含所有员工信息，每个员工有其对应的 Id, salary 和 department Id。

+----+-------+--------+--------------+
| Id | Name | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1 | Joe | 70000 | 1 |
| 2 | Henry | 80000 | 2 |
| 3 | Sam | 60000 | 2 |
| 4 | Max | 90000 | 1 |
+----+-------+--------+--------------+
Department 表包含公司所有部门的信息。

+----+----------+
| Id | Name |
+----+----------+
| 1 | IT |
| 2 | Sales |
+----+----------+
编写一个 SQL 查询，找出每个部门工资最高的员工。例如，根据上述给定的表格，Max 在 IT 部门有最高工资，Henry 在 Sales 部门有最高工资。

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT | Max | 90000 |
| Sales | Henry | 80000 |
+------------+----------+--------+

题目来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/department-highest-salary

思考：这应该是一道分组排序题目，先后先分组，然后排序，最好找出每组工资最高的。

解题：

思路只想到了第一步:查出id和最高工资。查询阻里最大的工资。

SELECT
    DepartmentId, MAX(Salary)
FROM
    Employee
GROUP BY DepartmentId;

然后，我们可以把表 Employee 和 Department 连接，再在这张临时表里用 IN 语句查询部门名字和工资的关系。

将两个表拼接起来，根据两个条件查询最后想要的结果。

SELECT
    Department.name AS 'Department',
    Employee.name AS 'Employee',
    Salary
FROM
    Employee
        JOIN
    Department ON Employee.DepartmentId = Department.Id
WHERE
    (Employee.DepartmentId , Salary) IN
    (   SELECT
            DepartmentId, MAX(Salary)
        FROM
            Employee
        GROUP BY DepartmentId
	);

类似的思路：

SELECT D.Name AS Department ,E.Name AS Employee ,E.Salary 
from 
	Employee E,
	Department D 
WHERE E.DepartmentId = D.id 
  AND (DepartmentId,Salary) in 
  (SELECT DepartmentId,max(Salary) as max FROM Employee GROUP BY DepartmentId)

也可以按照最初的思路，建立临时表，部门id和最高工资。然后三表查询想要的结果：

SELECT D.Name AS Department ,E.Name AS Employee ,E.Salary 
FROM
	Employee E,
	(SELECT DepartmentId,max(Salary) as max FROM Employee GROUP BY DepartmentId) T,
	Department D
WHERE E.DepartmentId = T.DepartmentId 
  AND E.Salary = T.max
  AND E.DepartmentId = D.id