LeetCode Convert Sorted List to Binary Search Tree
Convert Sorted List to Binary Search Tree
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
这题和上一题的用数组构建平衡二叉排序树比较类似,可以通过把List转换成Array之后在进行操作。具体用Array构建的方法见:
但是这种办法的时间和空间复杂度都是O(n);
这里参考
网上的办法有一个空间复杂度O(n),时间复杂度为O(1)的算法
TreeNode *sortedListToBST(ListNode *head)
{
int len = 0;
ListNode * node = head;
while (node != NULL)
{
node = node->next;
len++;
}
return buildTree(head, 0, len-1);
}
TreeNode *buildTree(ListNode *&node, int start, int end)
{
if (start > end) return NULL;
int mid = start + (end - start)/2;
TreeNode *left = buildTree(node, start, mid-1);
TreeNode *root = new TreeNode(node->val);
root->left = left;
node = node->next;
root->right = buildTree(node, mid+1, end);
return root;
}