import re
##匹配列表内的非负整数list=[99,100,-100,-1,90]
pattern = re.compile(r'[1-9]\d*|0')for i inlist:
m = pattern.search(str(i))print(m)##匹配列表内的整数list=[99,100,-100,-1,90]
pattern = re.compile(r'[1-9]\d*')for i inlist:
m = pattern.match(str(i))print(m)##匹配列表内的非正整数list=[99,100,-100,-1,90]
pattern = re.compile(r'-[1-9]\d*|0')for i inlist:
m = pattern.match(str(i))print(m)# ##正则匹配邮箱
c = re.compile(r'^\w+@(\w+\.)+(com|cn|net|edu)$')
string ='50772618@qq.com'
s = c.search(string)if s:print(s.group())##匹配十一位手机号
c = re.compile(r'^1[3-9]\d{9}$')
s = c.search('18785397892')if s:print(s.group())
c = re.compile(r'^[1-9]\d*|0$')
s = c.search('')if s:print(s.group())##正则匹配日期
pattern = re.compile(r'[1-9]\d{3}-(1[0-2]|0?[1-9])-(3[0-1]|[1-2]\d|0?[1-9])')#定义匹配模式
string ='hgfdjyjhfdjjj,2019-12-19jhgfjhgfjhf'
s = re.search(string)print(s.group())print(pattern.search(string,s.end()+1))##匹配密码
pattern = re.compile(r'[A-Z]\w{7,9}')
m = pattern.search('basldaE3217894_324yiudasjl')if m :print(m.group())