//获取子节点的所有父级
function getAllParent(treeJq, node) {
var parents = [];
function getParents(treeJq, node) {
var parent = treeJq.tree(“getParent”, node.target);
if (parent) {
parents.push(parent);
getParents(treeJq, parent);
} else {
return;
}
}
getParents(treeJq, node);
return parents;
获取easyui tree下节点的所有父级
最新推荐文章于 2022-07-10 22:35:56 发布