Python
class Solution:
def minPathSum(self, grid: List[List[int]]) -> int:
m = len(grid) # m行
n = len(grid[0]) # n列
matrix = [[0 for _ in range(n)] for _ in range(m)]
matrix[0][0] = grid[0][0]
for i in range(1, m):
matrix[i][0] = grid[i][0] + matrix[i-1][0]
for j in range(1, n):
matrix[0][j] = grid[0][j] + matrix[0][j-1]
for i in range(1, m):
for j in range(1, n):
matrix[i][j] = grid[i][j] + min(matrix[i-1][j], matrix[i][j-1])
return matrix[m-1][n-1]
Java
法1:二维DP
必须掌握!
class Solution {
public int minPathSum(int[][] grid) {
int m = grid.length, n = grid[0].length;
int[][] matrix = new int[m][n];
matrix[0][0] = grid[0][0];
for (int i = 1; i < n; ++i) {
matrix[0][i] = matrix[0][i - 1] + grid[0][i];
}
for (int i = 1; i < m; ++i) {
matrix[i][0] = matrix[i - 1][0] + grid[i][0];
}
for (int i = 1; i < m; ++i) {
for (int j = 1; j < n; ++j) {
matrix[i][j] = Math.min(matrix[i - 1][j], matrix[i][j - 1]) + grid[i][j];
}
}
return matrix[m - 1][n - 1];
}
}