题目
法1:DP
Python
class Solution:
def rob(self, nums: List[int]) -> int:
if len(nums) == 1:
return nums[0]
dp = [-1] * len(nums)
dp[0] = nums[0]
dp[1] = max(nums[0], nums[1])
for i in range(2, len(nums)):
dp[i] = max(dp[i-1], dp[i-2] + nums[i])
print(f'i={i}, val={dp[i]}')
return dp[len(nums) - 1]
Java
class Solution {
public int rob(int[] nums) {
int n = nums.length;
if (n == 1) {
return nums[0];
}
if (n == 2) {
return Math.max(nums[0], nums[1]);
}
int pre0 = nums[0], pre1 = Math.max(nums[0], nums[1]), max = 0;
for (int i = 2; i < n; ++i) {
max = Math.max(pre0 + nums[i], pre1);
pre0 = pre1;
pre1 = max;
}
return max;
}
}