select l.id, l.name, l.dept, l.salary
from employee as l
join (select max(salary) as salary, dept
from employee
groupby dept) as r
on l.dept = r.dept and l.salary = r.salary
哀酱4869的博客 ---------------------------------建表完成---------------------------- -- 3、查询薪资占比 SELECT dep.name AS department ,emp.name AS employee ,salary ,proportion FROM ( -- 2、取每个部门工资排前三的...
大数据之眸的博客获取所有部门中当前员工薪水最高的相关信息,给出dept_no, emp_no以及其对应的salary CREATE TABLE `dept_emp` ( `emp_no` int(11) NOT NULL, `dept_no` char(4) NOT NULL, `from_date` date NOT NULL, `to_date` ...