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- 接着奏乐吧 2021-10-20 10:31关注
#include <stdio.h> int main() { int t1 = 1, t2 = 1, nextTerm = 0, n,inx=3; printf("输入一个正数: "); scanf("%d", &n); // 显示前两项 printf("斐波那契数列: \n第1项=%d\n第2项=%d\n", t1, t2); nextTerm = t1 + t2; while(inx <= n) { printf("第%d项=%d\n",inx,nextTerm); t1 = t2; t2 = nextTerm; nextTerm = t1 + t2; inx++; } return 0; }
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