Ajax表单返回错误

Question

I am trying to post a form through AJAX in Netsuite so that I could trigger an event after the form submit without actually reloading it.

Please help me out, I am a newbie with AJAX.

Here is the code

$('#du_joinnow').submit(function(e){
  e.preventDefault(); //STOP default action
  var formdata = $(this).serializeArray();
  $.ajaxSubmit({
    type: "POST",
    url: "https://forms.na1.netsuite.com/app/site/crm/externalleadpage.nl?compid=XXXXXX&formid=1&h=XXXXXXXXXXXXXX"+ formdata,
    data: formdata,
    success:function(data, textStatus, jqXHR) {
      $('#overlay').fadeIn(); //data: return data from server
    },
    error: function(jqXHR, textStatus, errorThrown) {
      alert("Ajax Call Failed.");//if fails
    }
  });
  return false;
});

Answer 1

Instead of $.ajaxSubmit do $.ajax

Full Code:

$('#du_joinnow').submit(function (e) {
    e.preventDefault(); //STOP default action
    var formdata = $(this).serializeArray();
    $.ajax({
        type: "POST",
        url: "https://forms.na1.netsuite.com/app/site/crm/externalleadpage.nl?compid=XXXXXX&formid=1&h=XXXXXXXXXXXXXX" + formdata,
        data: formdata,
        success: function (data, textStatus, jqXHR) {
            $('#overlay').fadeIn(); //data: return data from server
        },
        error: function (jqXHR, textStatus, errorThrown) {
            alert("Ajax Call Failed."); //if fails
        }
    });
    return false;
});