Minimum Operations to Make Array Increasing Using Python

Suppose we have an array nums. In one operation, we can select one element of the array and increase it by 1. For example, if we have [4,5,6], we can select element at index 1 to make the array [4,5,5]. Then we have to find the minimum number of operations required to make nums strictly increasing.

So, if the input is like nums = [8,5,7], then the output will be 7, because we need to increase like [8,6,7],[8,7,7],[8,8,7],[8,9,7],[8,9,8],[8,9,9],[8,9,10].

To solve this, we will follow these steps −

• count:= 0

• for i in range 0 to size of nums - 1, do

  • if nums[i+1] −= nums[i], then

    • count := count + nums[i] - nums[i+1] + 1

    • nums[i+1] := nums[i+1] + nums[i] - nums[i+1] + 1

• return count

Let us see the following implementation to get better understanding −

Example

 Live Demo

def solve(nums):
   count=0
   for i in range(len(nums)-1):
      if nums[i+1]<=nums[i]:
         count+=nums[i]-nums[i+1]+1
         nums[i+1]+=nums[i]-nums[i+1]+1
   return count
nums = [8,5,7]
print(solve(nums))

Input

[8,5,7]

Output

7