Find Length of Longest Balanced Subsequence in Python

Suppose we have a string s containing brackets parenthesis "(" and ")", we have to find the length of the longest subsequence of balanced brackets.

So, if the input is like s = "())(()(", then the output will be 4, as we can take the subsequence like "()()"

To solve this, we will follow these steps −

• res := 0

• n := size of s

• close := 0

• for i in range n - 1 to 0, decrease by 1, do

  • if s[i] is same as ")", then

    • close := close + 1

  • otherwise,

    • if close > 0, then

      • close := close - 1

      • res := res + 2

• return res

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:
   def solve(self, s):
      res = 0
      n = len(s)
      close = 0
      for i in range(n - 1, -1, -1):
         if s[i] == ")":
            close += 1
         else:
            if close > 0:
               close -= 1
                  res += 2
            return res
ob = Solution()
s = "())(()("
print(ob.solve(s))

Input

"())(()("

Output

4