How to handle multiple exceptions while array is out of bound in Java

Problem Description

How to handle multiple exceptions while array is out of bound?

Solution

This example shows how to handle multiple exception methods by using System.err.println() method of System class.

public class Main {
   public static void main (String args[]) {
      int array[] = {20,20,40};
      int num1 = 15, num2 = 10;
      int result = 10;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         for(int i = 5; i >= 0; i--) {
            System.out.println("The value of array is" +array[i]);
         }
      } catch (ArrayIndexOutOfBoundsException e) {
         System.out.println("Array is out of Bounds"+e);
      } catch (ArithmeticException e) {
         System.out.println ("Can't divide by Zero"+e);
      }
   }
}

Result

The above code sample will produce the following result.

The result is1
Array is out of Boundsjava.lang.ArrayIndexOutOfBoundsException : 5