Find the Center of a Circle Using Endpoints of Diameter in C++

Suppose we have two endpoints of diameter of a circle. These are (x1, y1) and (x2, y2), we have to find the center of the circle. So if two points are (-9, 3) and (5, -7), then the center is at location (-2, -2).

We know that the mid points of two points are −

$$(x_{m},y_{m})=\left(\frac{(x_{1}+x_{2})}{2},\frac{(y_{1}+y_{2})}{2}\right)$$

Example

 Live Demo

#include<iostream>
using namespace std;
class point{
   public:
      float x, y;
      point(float x, float y){
         this->x = x;
         this->y = y;
      }
      void display(){
         cout << "(" << x << ", " <<y<<")";
      }
};
point center(point p1, point p2) {
   int x, y;
   x = (float)(p1.x + p2.x) / 2;
   y = (float)(p1.y + p2.y) / 2;
   point res(x, y);
   return res;
}
int main() {
   point p1(-9.0, 3.0), p2(5.0, -7.0);
   point res = center(p1, p2);
   cout << "Center is at: ";
   res.display();
}

Output

Center is at: (-2, -2)