Count and Print Alphabets with ASCII Values Outside a Range in C++

We are given with a string of any length and the task is to calculate the count and print the alphabets in a string having ASCII value not in the range [l,r]

ASCII value for character A-Z are given below

ASCII value for characters a-z are given below

For Example

Input − String str = “point
      First = 111, Last = 117
Output − characters not in the given range are: i, n
      Count is: 2

Explanation − since i and n don't lies in the range of [111, 117] these characters will be counted.

Input − String str = “ABCZXY
      First = 65, Last = 70
Output − characters in the given range are: A, B, C
      Count is: 3

Explanation − since Z, X and Y don’t lie in the range of [65, 70] these characters will be counted.

Approach used in the below program is as follows

• Input the string, start and end values to create the range and store it in variables let’s say, str.

• Calculate the length of the string using the length() function that will return an integer value as per the number of letters in the string including the spaces.

• Take a temporary variable that will store the count of characters and create a map let’s say, mp

• Start the loop from i to 0 till i is less than the length of the string

• Inside the loop, check if start is less than not equals to str[i] and str[i] is less than not equals to end

• Inside the if, check if mp[str[i]] ! = 1 then print str[i] else increase mp[str[i]] by 1

• Return the count

• Print the result

Example

 Live Demo

#include <iostream>
#include <unordered_map>
using namespace std;
// To count the number of characters whose
// ascii value not in range [l, r]
int count_non_char(string str, int left, int right){
   int count = 0;
   // using map to print a character only once
   unordered_map<char, int> m;
   int len = str.length();
   for (int i = 0; i < len; i++) {
      if (!(left <= str[i] and str[i] <= right)){
         count++;
         if (m[str[i]] != 1){
            cout << str[i] << " ";
            m[str[i]]++;
         }
      }
   }
   // return the count
   return count;
}
// main code
int main(){
   string str = "tutorialspoint";
   int left = 102, right = 111;
   cout << "Characters and ";
   cout << "\nand count in the given range is: " << count_non_char(str, left, right);
   return 0;
}

Output

If we run the above code it will generate the following output −

Characters and
and count in the given range is: t u r a s p 8