Skip to content

Runaway recursion with keyword arguments in 3.14 #137883

Description

@jrivers0

Bug report

Bug description:

def f(a=0):
    f(a=0)
f()

This code causes an infinite loop (until it runs out of memory) in Python 3.14. It raises RecursionError in Python 3.13. There is no problem when calling the function without a keyword argument; in that case, it also raises RecursionError as expected.

CPython versions tested on:

3.13, 3.14, CPython main branch

Operating systems tested on:

macOS

Linked PRs

Activity

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment

Metadata

Metadata

Assignees

No one assigned

    Labels

    3.14bugs and security fixes3.15pre-release feature fixes, bugs and security fixesinterpreter-core(Objects, Python, Grammar, and Parser dirs)release-blockertype-bugAn unexpected behavior, bug, or error

    Projects

    Milestone

    No milestone

    Relationships

    None yet

    Development

    No branches or pull requests

    Issue actions