CANNOT INSERT "LAST INSERT ID" IN 3 TABLES?

On Ln95, you're setting last_id to last_insert_id when last_insert_id is the query for INSERT INTO directives

If I see it right, you have 12 table rows and 11 values in your sqr1.
This will give a error and will insert noting, giving you no last_insert_id

tip: paste your code next time - make it easy for contributors. Images are difficult to read.

The biggest problem with that code is that - unless it's done in the code you hid between the first two queries - you seem to be executing the queries regardless of what happened with the previous query. If the first query fails, you still execute the second query, and then the third query. You need to check the return value of the queries and make sure they were successful before moving on to the next.

Another kind of catastrophic issue there is that you inject user input directly int the query string. That's a huge security risk. You should read up on SQL Injection.

One more thing that jumps out at me is that when you do chained inserts like that, you usually want them all to succeed, or all to fail. You don't want the first two to succeed, but the third to fail, leaving you with a half finished chain of inserts. - To prevent that, you would normally use transactions. Unfortunately the old MySQL API functions (mysql_query and the rest of that family) are ancient and do not support them. They should no longer be used. You should be using MySQLi or PDO instead. They also support prepared statements, which protects you from the SQL Injection riks.

thanks diafol, atli and others for cooperating.
well actually when i echo the values from the query.it works till the sql query2.the sql3 do not works out.well ill gona try for mysqli and pdo but for time being i need to figure it out with the same scenario.
cant we store the initial last_id value in a variable and then re-use accordingly to the need; as in sql3 query, if yes the how ? or any other method ?