If I have an integer like x = 12345, how do I separate that into individual integers 1, 2, 3, 4, 5?
sneekula 969 Nearly a Posting Maven
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Jump to PostIf you wanted to use the digits of an integer, you could convert to a string like mawe suggested and then use the indexed string elements ...
x = 12345 s = str(x) print s[0] # 1 print s[1] # 2 print s[2] # 3 print s[4] …
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mawe 6 Junior Poster
Hi!
You have to convert the integer to an iterable (e.g. a string), then split it into a list, then convert the elements of the list back to integers:
x = 12345
newx = [int(i) for i in list(str(x))]Regards, mawe
vegaseat 1,735 DaniWeb's Hypocrite Team Colleague
If you wanted to use the digits of an integer, you could convert to a string like mawe suggested and then use the indexed string elements ...
x = 12345
s = str(x)
print s[0] # 1
print s[1] # 2
print s[2] # 3
print s[4] # 5
print type(s[2]) # <type 'str'>
# to get an integer value use
i = int(s[2])
print i # 3 sneekula 969 Nearly a Posting Maven
Python does make it look easy! Thank you!
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