Ok, so far i have 2 strings inputed from keyboars into stringA and stringB, defined as db
now i need to count how many times is string B appearing in A and output that number.
Max lenght of strings is 29.
I think it should be done in 2 loop, to run throgh bouth string,
Can anyone help?
mihal 0 Newbie Poster
Recommended Answers
Jump to PostThat sounds like a reasonable approach.
Jump to PostWell you use 'divide by 10' and 'modulo 10' to extract each digit from the number, then add '0' to the result to get a printable character.
123 / 10 = 12
123 % 10 = 3
Take the 3, add '0' to it to get '3'
The only …
All 5 Replies
Salem 5,265 Posting Sage
That sounds like a reasonable approach.
mihal 0 Newbie Poster
thats fine but now in need to print di which i uses as a counter, how to do it?
JobMatchNow 0 Light Poster
Is two loops even alot?
Salem 5,265 Posting Sage
Well you use 'divide by 10' and 'modulo 10' to extract each digit from the number, then add '0' to the result to get a printable character.
123 / 10 = 12
123 % 10 = 3
Take the 3, add '0' to it to get '3'
The only minor problem being that it gives you the digits in reverse order, but that shouldn't be that hard to solve.
mihal 0 Newbie Poster
Jeah in other words pul it all on Stack:) I used somthing simmilar:
First it writes message, then prints counter. Hers the code hope it helps someone, cheers
Print|Count proc far
push si
push ax
mov dx,offset message1
mov ah,09
int 21h
mov bx,10
mov si,2
mov ah,0
mov al,counter
Base10:
mov dx,0 ; zero devide
div bx
add dx,48
mov rez1+[si],dl;
dec si
cmp ax,0
jne Base10
mov dx,offset rez1
mov ah,09
int 21h
pop ax
pop si
ret
ispisbrojaca endp
Be a part of the DaniWeb community
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.